2. I took the q^2 and square rooted it, which is .13^(1/2) = .360
the square root of q^2 is q
3. After I got q I subtracted from 1 to get p which is .639 (so 1-.360 = .639)
4. Then I squared p to get p^2 which was .408 (so .639^2= .408)
5. To get 2pq I multiplied 2*.639*.360 which equals .46008 (so .46008 = 2pq)
To find the number of homozygous recessive individuals multilply q^2 (which is .13) by the population size (which is 1000). (so .13 * 1000 = 130) therefore there are 130 individuals that are homozygous recessive
To find the number of homozygous dominant individuals multiply P^2 (which is .408) by the population size (which is 1000) (so .408* 1ooo= 408) therefore there are 130 individuals that are homozygous recessive
To find the number of heterozygous individuals multiply 2pq (which is .46008) by the population size (which is 1000) (so .46008 * 1000 = 460.08 ) therefore there are 460.0 individuals that are heterozygous.
- q^2 is the frequency of the homozygous recessive individual (so the percentage of homozygous recessive individuals in a population )
- P^2 is the frequency of the homozygous dominant individual (so the percentage of homozygous dominant individuals in a populatiom )
- 2pq is the frequecny of the heterozygous individual
- p is the frequency of the dominant allele
- q is the frequency of the recessive allele
