H-Weezy

1.The q^2 given was .13 and the number of individuals in the population that was given was 1000
2. I took the q^2 and square rooted it, which is .13^(1/2) = .360
the square root of q^2 is q
3. After I got q I subtracted from 1 to get p which is .639 (so 1-.360 = .639)
4. Then I squared p to get p^2 which was .408 (so .639^2= .408)
5. To get 2pq I multiplied 2*.639*.360 which equals .46008 (so .46008 = 2pq)

To find the number of homozygous recessive individuals multilply q^2 (which is .13) by the population size (which is 1000). (so .13 * 1000 = 130) therefore there are 130 individuals that are homozygous recessive

To find the number of homozygous dominant individuals multiply P^2 (which is .408) by the population size (which is 1000) (so .408* 1ooo= 408) therefore there are 130 individuals that are homozygous recessive

To find the number of heterozygous individuals multiply 2pq (which is .46008) by the population size (which is 1000) (so .46008 * 1000 = 460.08 ) therefore there are 460.0 individuals that are heterozygous.

•  q^2 is the frequency of the homozygous recessive individual (so the percentage of homozygous recessive individuals in a population )
• P^2 is the frequency of the homozygous dominant individual (so the percentage of homozygous dominant individuals in a populatiom )
• 2pq is the frequecny of the heterozygous individual 
• p is the frequency of the dominant allele
• q is the frequency of the recessive allele 

California Blackworm Heart rate

Conclusion and how I came to it: I postulate that solution A is the water, solution B is the depressant, and solution C is the stimulant. I came to that conclusion because in the data in chose to look at, which was my groups, Mel's group, Kyle's group, and Shy's group, solution A was not the slowest pulse rate but it was not the fastest either. Solution C was the fastest and Solution B was slightly slower than solution A.

Method: First, I looked at all the data from all the groups and crossed out all the outliers, or the numbers that seemed extremely small, large, or that were not consistent with the majority of the other groups data. However, solution A of Shy's group data looks like an outlier but I did not cross it out for consistency because I used her other two solutions.

 Then I took each groups average of each solution and recorded it. I also Added all the groups averages for each solution. However, I did not add solution A of Shy's group data because it would skew the results since the number is so small.
Like so: (Mel's first one is 24.8 sorry for the messy handwriting!)

When looking at the data I put together, I observed that in every groups but shy data solution B had the slowest heart beat and solution C had the fastest, which means solution C is the stimulant and solution B is the depressant. Since solution A was not the fastest or slowest, I thought that one was water.

ecology scavenger hunt

 Heres some pics from my Ecology Selfie scavenger hunt. The first one is an abiotic factor (soil) the second one is thigomortropism, and the third one is mutualism, at first collecting these pictures were pretty hard to take becuase I HATE bugs and flies. Also, I had to learn how to take a good picture while including myself in it. All in all it was a great experience becuase not only did I learn the words from the scavenger hunt, I saw examples of them. Another thing I enjoyed about the scavenger hunt is that it made me think of how I was going to find the items. Like for mutualism I thought whats dependent on each other and I realized plants give us Oxygen while we give them CO2 which is why trees are so important. Also its really cool to think of how plants learned to behave the way they do and evolution. Like the plants that didnt learn how to coil the surface it was growing on died while the plants that were thigomotropic lived. to me thats very interestin how a plant could do that.